<span>(4x+1)^2-14x-2=0
16x^2+2*4x*1+1-14x-2=0
</span><span>16x^2-6x-1=0
x1=-0,125
x2=0,5
Ответ: </span>x1=-0,125 и <span>x2=0,5</span>
А)
=3х^2-6х
б)
=х^3у^2+2х^2у^3
^ знак степени
<span>sin(</span>π<span>/2 -</span>α<span>)tg(-</span>α<span>)/cos(</span>π<span>/2+</span>α<span>) =(cos</span>α)*(-tgα)*(-sinα) = sin^2α
A1=4-2=2
a9=4*9-2=34
S= (a1+a9)/2*9=(34+2)/2*9=162