(5^log₂7)^log₅2 = ?
Преобразуем log₂7 = log₅7 : log₅2
= 5^(log₅7 : log₅2 · log₅2) = 5^(log₅7) = 7
Ответ: 7
y=sqrt(3x-2)*sqrt(x-5)=sqrt((3x-2)(x-5))=sqrt(3х^2-2x-15x+10)=sqrt(3х^2-17x+10)