1) ∫x²dx = x³/3 + C
1 = 2³/3 + C
C = 1 - 8/3 = - 5/3
2) ∫40dx = = 40x + C
2 = 40×5 + C
C = 2 - 200 = -198
3) ∫sin(x)dx = - cos(x) + C
-1 = -cos(π) + C
C = cos(π) - 1 = -1 - 1 = -2
(x+3.4)(9x-10)=(x+3.4)(10x-9)
9x²-10x+30.6x-34=10x²-9x+34x-30.6
10x²-9x+34x-30.6-9x²+10x-30.6x+34=0
x²+4.4x+3.4=0
D=4.4²-4*3.4=19.36-13.6=5.76=2.4²
x(1)=(-4.4+2.4)/2=-2/2=-1
x(2)=(-4.4-2.4)/2=-6.8/2=-3.4
меньший корень -3.4
Решение на фотографии! !!!!!!!!!!!!!!!!