Sin(α + β) = sinα · cosβ + cosα · sinβ
sin(π/3 + α) - √3/2cosαα α = 0,
sinπ/3 · cosα + cosπ/3 · sinα - <span>√3/2cosαα α = 0,
</span>√3/2cosαα α + cosπ/3 · sinα - <span>√3/2cosαα α = 0,
</span><span>cosπ/3 · sinα = 0,
</span>1/2 · <span>sinα = 0,
</span><span>sinα = 0,
</span>α = πn, n ∈ Z
Sin(x/4+5*π/6)=-1/2⇒x/4+5*π/6=arcsin(-1/2)=-π/6 ⇒х/4=-<span>π/6-5*</span>π/6=-π⇒х=-4*π.
Ответ: х=-4*π
9y²-(3y-1)(3y-2)= -16
9y²-9y²+6y+3y-2= -16
6y+3y= -16+2
9y= -14
y= -14/9.