Х*(х-у)-3(х-у)
1/2 * (1/2 - 1/4)-3*(1/2 -1/4) =1/2 *1/4 - 3*1/4 =1/8 - 3/4 =(1-6)/8 = - 5/8
Решение
<span>y=√(cosx+1)
cosx + 1 </span>≥ 0
cosx ≥ - 1
- arccos(-1) + 2πn ≤ x ≤ arccos(-1) + 2πn, n ∈ Z
- π <span>+ 2πn ≤ x ≤ </span>π<span> + 2πn, n ∈ Z</span>
2x-25-7
6y+y-3
16a-25b-16a²+48ab
8m+9n+4m-36n
2x-2x-2x+9
вроде так)