Решение
х+2у=1
<span>2х^2+3ху-3у^2=6
</span>
x = 1 - 2y
2(1 - 2y)² + 3*(1 - 2y)*y - 3y² = 6
x = 1 - 2y
2*(1 - 4y + 4y²) + 3*(y - 2y²<span>) - 3y² = 6
</span>x = 1 - 2y
2 - 8y + 8y² + 3y - 6y² - 3y² = 6<span>
- y</span>² - 5y - 4 = 0
y² + 5y + 4 = 0
y₁ = - 4
y₂ = - 1
y₁ = - 4
<span>x = 1 - 2*(-4)
x</span>₁ = 9
y₁ = - 4
y₂ = - 1
<span>x = 1 - 2*(-1)
</span>
x₂ = 3
y<span>₂ = - 1
</span>
Ответ: (9; - 4) ; (3; - 1)
-0,3x+5,4=0,2x-8,4
0,2x+0,3x=5,4+8,4
0,5x=13,8
x=138:5
x=27,6
y=0,2*27,6-8,4=5,52-8,4=-2,88
(27,6;-2,88)