<em>Решение:</em>
<em>S=½h(a+b) - формула площади </em><em>трапеции</em><em>.</em>
<em>S=½ * 8 * (3+6) = 4 * 9 = 36.</em>
<em>Ответ: </em><em>36.</em>
По теореме Пифагора находим на всякий случай катет АС = √10²-8² = 6.
BM - медиана, AM=CM
В равнобедренном треугольнике медиана является высотой, BMA=BMC=90
Треугольники AOM и COM равны по двум катетам (OM - общий), AO=CO
Ответ:
ABCD - трапеция (AD=20, BC=10. L A = L B = 60).
Проведи высоту ВК из вершины В на основание AD.
Рассмотри прямоугольный треугольник АВК.
АК = (AD - BC)/2 = (20 - 10)/2 = 5
BK = AK * tg 60 = 5 * V3 = 5V3 - высота трапеции
Площадь трапеции
S = (AD + BC)/2 * BK = (20 + 10)/2 * 5V3 = 75V3 = 129,75
как то так
This autumn my mother, sister and me traveled to Spain. It took us much time to get to Spain, but it was worth it. I was very surprised to find out that the weather in Spain is hot, because in Russia it was too cold. Many people in Spain do not speak Russian, many people wear very simple clothes, and it was difficult to get used to.
There we met many children. We did not notice that they did not understand us. We were friends and played together. My family and I often walked along the streets. It was wonderful. Streets in Spain are very clean. We also visited a large aquarium. There we saw different fishes, sharks, and rays. We spent two weeks in Spain.
When we came back to Russia it was already snowing here. I enjoyed the trip.