<span>1) cos(3arctg(-1/</span>√<span>3))=cos(-3arctg 1/</span>√<span>3)=cos(3arctg 1/</span>√<span>3)=cos(3*</span>π/6)=cos π/2=0.<span>
2) sin(2arctg(-1))=sin(-2arctg 1)=-sin(2arctg 1)=-sin(2*</span>π/4)=-sin π/2=-1.
Приравниваем оба уравнения и получаем
8/х=х/2
х²=16
х1=4
х2=-4
у1=8/4=2
у2=8/(-4)=-2
ответ:(4;2);(-4;-2)