Cd²=ad*dbcd²=144x²cd=12x12x=4.8x=0.416*0.4=6.4= ad9*0.4=3.6=db<span>Значит, АВ=10</span>
S=((2*(-1,5)+9*2)*10)/2=75
(8·5x¹⁷ +11·5x¹⁸) / (5x⁹·3)²·7=5x¹⁷(8+11·5) /5²·x¹⁸·3²·7=
=5¹⁻²·x¹⁷⁻¹⁸·(8+55)·3⁻²·7⁻¹=5⁻¹·x⁻¹·63·3⁻²·7⁻¹=
=5⁻¹·x⁻¹·7¹⁻¹·3²⁻²=(5x)⁻¹=1/5x
cos4x-sin3x cosx+cos2x=0;
Во вложении..................