1
((a^5/6)^6=a^5=[(1/3)^2/5)]^5=(1/3)^2=1/9
2
(a^7/12)^12=a^7=[(3/4)^2/7]^7=(3/4)^2=9/16
3
(a^-1/3)^30=a^-10=[(1/2)^-2/5]^-10=(1/2)^4=1/16
4
(a^-1/4)^20=a^-5=[(3/10)^-2]^-5=(3/10)^2=9/100
64-16x+x²=13x+10
x²-16x-13x+64-10=0
x²-29x+54=0
D=841-216=625
x1= (29-25)/2=2
x2=(29+25)/2=27
Решение
sin^6(a)+cos⁶(a) = (sin²a)³ + (cos²a)³ =
(sin²a + cos²a)*(sin⁴a - sin²acos²a + cos⁴a) =
= [(sin⁴a + 2sin²acos²a + cos⁴a) - 3sin²acos²a] =
(sin²a + cos²a)² - 3sin<span>²acos²a =
= 1 - </span>3sin²acos²a = 1 - (3/4)*(2sinacosa)*(<span>2sinacosa) =
= 1 - (3/4)*(sin</span>²2a) = 1 - [(1 - cos4a)/2] =
= 1 - 3/8 + (3/8)*cos4a = 5/8 + <span> (3/8)*cos4a = (1/8)*(3cos4a + 5)</span>
(-4аб³)²=16а²б^6
б^6 - это б в 6 степени