A) sinx = √3/2; x =
∈Z; sinx (sin2x + 1) = 0;
sinx = 0; x = πn, sin2x =- 1; sinx = -1/2; x =
2) 2 cosx/2 меньше 1; cosx/2 = 1/2; x/2 =π/6 +2πn, n∈Z; x =+- π/3 +πn,n∈z;
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A²-10ab+25b²=(a-5b)²
25+10x+x²=(5+x)²
k⁴+2k²+1=(k²+1)²
p²-1,6p+0,64=(p-0,8)²
А1)1
А2)2
А3)4
А4)3
В1)(x+2,5)(x+1)>=0
x<=-2,5
x>=-1
ответ (-беск.;0] [-1;+беск)
4xy-y²/5xy+x²
y(4x-y)/x(5y+x)
4x-y/4(5y+x)
4x-y/20y+4x
4x-0.25x/5x+4x
3,75x/9x
3,75x/36y
15/36
Ответ: 15/36