(2x-3)2^=4х2^-25-2=4х2^-27
(2x-3)2^= (2x-3)2^
3sin 2x+2sin (П/2+2x) = 3
3sin2x+2cos2x=3
6sinxcosx+2(1-2sin^2x)=3(sin^2x+cos^2x)
-7sin^2x+6sinxcosx-3cos^2x=-2
5sin^2x-6sinxcosx+cos^2x=0 /:cos^2x≠0
5tg^2x-6tgx+1=0
D=16>0
tgx=1⇒x=pi/4+pik, k∈Z
tgx=1/5⇒x=arctg1/5+pin, n∈Z
ОТВЕТ: pi/4+pik, k∈Z
arctg1/5+pin, n∈Z
(3ab-3a²)*(2a+ 2b) 3a*(b-a)*2*(a+b) -3a*(a-b)*2*(a+b)
-------------------------- = --------------------------- = --------------------------- = - 6a
a²-b² (a-b)(a+b) (a-b)(a+b)
У = ⁺- arccos 1\2 + 2πn, n ∈ Z
y = ⁺- π\3 + 2πn