5460 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
3)a^2-4ac+4bc^2=(ab-2bc)^2
(3n-10)/n=k, k- натуральное.
3n-10=nk,
3n-nk=10
n(3-k)=10
n=10/(3-k)
n-целое, значит 3-k
3-k =1 или 3-k=2 или 3-k=5 или 3-k=10
k=2 k=1 k=-2<span>∉N</span> k=-7<span>∉N
</span>n=10 n=5
3-k =-1 или 3-k=-2 или 3-k=-5 или 3-k=-10
k=4 k=5 k=8 k=13<span>
</span>n=-10 n=- 5 n=-2 n=-1
О т в е т. -10; -5; -2; -1; 5; 10
0.7y - 0.2x + 0.3y +0.2x = 1y = -0.14