2x^2-18x+36=0
Д=324-4×2×36=36
х1=18+6/4=6
х2=18-6/4=3
.................................
Решение
<span>4(4x−23)^2−19(4x−23)+12=0
</span>4x - 23 = z
4z² - 19z + 12 = 0
D = 361 - 4*4*12 = 169
z₁ = (19 - 13)/8
z₁ = 0,75
z₂ = (19 + 13)/8
z₂ = 32/8
z₂ = 4
4x - 23 = 0,75
4x = 0,75 + 23
x₁ = 23,75/4
x₁ = 5,9375
4x - 23 = 4
4x = 4 + 23
4x = 27
x₂ = 6,75
Ответ: x₁ = 5,9375 ; x₂ = 6,75
<span>(x−1)^2 / x^2+4x−5
2х-2/2х+4х-5
2х-2/6х-5</span>