(2x - 5) + (- 3x +16) = (- x + 11)
B₁ + b₁ q + b₁ q² = 78/125
b₁ (1 + q + q² )= 78/125 |q| < 1
S = b₁/(1-q)
b₁ = S/(1 - q) = 2/3(1 - q)
2/3(1-q)(1+q+q²) = 78/125
1 - q³ = 78/125 : 2/3
1 - q³ = 117/125
q³ = 1 - 117/125 = 8/125
q = ∛8/125 = 2/5
b₁ = S * (1 - q) = 2/3 * (1 - 2/5) = 2/3 * 3/5 = 2/5 = 0,4
В <span>y(5y+2x) - (x+y)^2 </span>получилось 23 ответ.
(a-2b)*(a+2b)+(2b+1)^2-2a = a² + 2ab - 2ab - 4b² + 4b² + 4b +1 -2a = a² + 4b +1 -2a