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A)
f ' (x) = 1/3*3x^2 + 2x + 2 = x^2 + 2x + 2
b)
f ' (x) = (2/x^3 - x) ' = 2*(1/x^3) ' - (x)' = 2*(x^(-3))' - 1 =
= - 3*2*x^(-4) - 1 = - 6x^(-4) - 1
1) а+б-10аб=6а-2аб-3аб+6б-5аб-5а-5б;
а+б-10аб=а+б-10аб. Только зачеркни же)
2)
8-12m-6+m-6m-8=-17m-6;
-17m-6=-17m-6
Тождество доведено
4-1,19/15= (60-1,19)/15=58,81/15=3целые13,81/15
23x^2-2x+1=1
23x^2-2x=0
x(23x-2)=0
x=0 или 23x=2
x=2/23