Sinxcos2x + cosxsin2x = 0
sin(x + 2x) = 0
sin3x = 0
3x = πk, k∈Z
x = πk/3, k∈Z
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√(9-4√5)=√(5 -4√5+4) =√(√5²-4√5 +2²)= √(√5-2)²= √5 - 2
√(7-2√6)= √(6-2√6+1) =√(√6² -2√6+1²)= <span>√(√6-1)</span>²=√6 -1
Sina/cosa:[cosa/sina*1/cos²a)-1=sina/cosa*sinacosa-1=sin²a-1=-cos²a
1) f ' (x)=14(x-5)¹³
f ' (4)=14(4-5)¹³= -14
2) f ' (x)=24(3x-11)⁷
f ' (4)=24(3*4-11)⁷=24
3) g ' (x)= -35(x-6)⁻⁶ = -35/(x-6)⁶
g ' (7)= -35/(7-6)⁶= -35
4) y ' (x)= -60(4x-9)⁻⁴= -60/(4x-9)⁴
y ' (2)= -60/(4*2-9)⁴= -60