1)1-0,125m^3=1^3-(0,5m)^3= (1-0,5m)(1+0,5m+0,25m^2)
2)(2x+y)^3-x^3= (2x+y-x)*[(2x+y)^2+x(2x+y)+x^2]= (x+y)(4x^2+4xy+y^2+
+2x^2+xy+x^2)= (x+y)(7x^2+5xy+y^2)
6x²-5x +1=0
D= b² - 4ac = (-5)² -4*6*1 = 25-24=1
x1= -b+√D 5+1 6 1
_____ = _____ = ___ = __
2a 2*6 12 2
x2 = -b-√D 5-1 4 1
_____ = ____=__=__
2a 2*6 12 3
Ответ: 0.5 и 1/3
sin*cos = 1 => 3sin*cos = 3
Х*(49х2+14х+1)=0
х*(7х+1)2=0
х1=-1/7
х2=0