<span><span>2 <span>CH3COOK</span></span> + <span>H2SO4</span>→<span>K2SO4</span>+<span>2<span>CH3COO
</span></span></span><span><span><span>C2H6O</span></span>+<span>2<span>K2Cr2O7</span></span>+<span>8<span>H2SO4</span></span>→<span>3<span>CH3COOH</span></span>+<span>2<span>Cr2<span>(SO4)</span>3</span></span>+<span>2<span>K2SO4</span></span>+<span>11<span>H2<span>O
</span></span></span></span>
Х г 2,9 г
MgCl2 + 2NaOH -> Mg(OH)2 + 2NaCl
n=2 моль n=1 моль
М = 40 г/моль М = 58 г/моль
m=80 г m=58 г
Х г NaOH - 2,9 г Mg(OH)2
80 г NaOH - 58 г Mg(OH)2
m(NaOH) = 80 * 2,9 / 58 = 4 г
NaOH+Cu(NO3)2=NaNO3+Cu(OH)2
Дано:
N(H₂S) = 6 ·10²³
V(H₂S) -?
решение:
n(H₂S) = N\Na = 6 · 10²³ \ 6,023 · 10²³ моль = 0,996 моль
V(H₂S) = Vm · n = 22,4 л\моль · 0,996 моль = 22,32 л
<span>Ответ: 22, 32л</span>