(x-2)(x2+2x+4)+(x2+4x+4-2x)=(x-2)(x2+2x+4)+(x2+2x+4)=(x2+2x+4)(x-1) изи
1/((1-i)^3)=1/((1-i)*(1-i)^2)=1/((1-i)(1-2i+i^2))=1/((1-i)(1+2i-1))=1/((1-i)*2i)=1/(2i-2i^2)
=1/(2i-2)
P.S. i^2=-1
9n-12m-10m-5n
4n-22m
4*3+22*2=12+44=56
9х + 9 = 10х + 7
9х -10х = 7 - 9
-х = -2 | : (-1)
х = 2