√((3,02-2,98)/√(40²-32²))=
=√((3,02+2,98)(3,02-2,98)/√(40+32)(40-32))=
=√((6*0,04/√(72*8))=√(6*0,04/24)=√0,01=0,1.
√(66√(50²-40²)/√(44²+33²))=√(66√((50+40)(50-40))/√3025)=
=√(66√900/55)=√(66*30/55)=√(180/5)=√36=6.
1-(x-3)^2=0
(1-x+3)(1+x-3)=0
(4-x)(x-2)=0
4-x=0 или x-2=0
x=4 x=2
Ответ:x=4
x=2