A²*sin2π +2ab*cos3π/2 +c³*tg2π = a²*0+2ab*0+c³*0=0+0+0=0
a³*ctg270°+b³*tg0° = a³*0+b³*0= 0+0 =0
<span>(3x+y)^2+(3xy-1)^2-(3x-y)^2=
</span>((3x+y)+(3x-y))(<span>(3x+y)+<span>(3x-y))</span>+(3xy-1)^2=
</span>(6x)(<span>2y)+(3xy-1)^2=</span>(12xy)+(3xy)^2-<span>6xy+1=
</span>=(3xy)^2+<span>6xy+1=</span>(3xy+1)^2=(3xy+1)(3xy+1)
Ответ:
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Объяснение: