(x-a)/(a+3)=(a-4)/(x-a)
(x-a)²=(a+3)(a-4) ⇒
(a+3)(a-4)<0
-∞_____+_____-3_____-_____4_____+_____+∞
a∈(-3;4).
(2^6)^x²-3x+20)<(2^-3)^2x²-6x-200
2^6x²-18x+120<2^-6x²+18x+600
6x²-18x+120<-6x²+18x+600
6x²-18x+120+6x²-18x-600<0
12x²-36x-480<0
x²-3x-40<0
x1+x2=3 U x1*x2=-40⇒x1=-5 U x2=8
+ _ +
_____________________________________________
-5 8
x∈(-5;8)
<span>Все,что знаю:</span>