Y=(x+1)/(x²+3)=0
y`=((x+1)`*(x²+3)-(x+1)*(x²+3)`)/(x²+3)²=0
(1*(x²+3)-(x+1)*2x)/(x²+3)²=0
(x²+3-2x²-2x)/(x²+3)²=0
-(x²+2x-3)/(x²+3)=0 |×(-1)
(x²+2x-3)/(x²+3)=0
x²+3>0 ⇒
x²+2x-3=0 D=16
Ответ: x₁=1 x₂=-3.
1) У=Х-1
2)У=-1/3Х-1/6
3)У=-3Х+7
4)У=-4/3Х+7/3
5)У=0Х+16
6)У=2Х+4
<span>3*(5-x)+13=4*(3x-8)
15-3х+13=12х-32
-3х-12х=-15-32-13
15х=34
х=34:15
х=34/15
х=2целых 4/15</span>
<=>{x=3-y <=>{y=7 <=>{y=7
{3*3-y=13 {×=3-y {×=-4
__________ ______
-y=13-6 x=3-7
-y=7 x=-4
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