2)y=-3
3)f`(x)=39x²-7x
f`(0)=0
f`(-1)=39+7=46
f`(0)+f`(-1)=0+46=46
4)y`=-2x/2√(x²+1)³=-1/√(x²+1)³
5)y`=24(1/3x-64)^23 * 1/3=8(1/3x -64)^23
6)y`=1/cos²x
y`(π/3)=1/cos²π/3=1:1/4=4
7)tga=f`(x0)
f`(x)=6x²-5
f`(2)=6*4-5=24-5=19
tga=19
8)f(x)=x^8 -1
f`(x)=8x^7
9)y`=8cos3x*(-sin3x)*3=-24cos3xsin3x=-12sin6x
10)f(x)=1-4x²
f`(x)=-8x
f`(0,5)=-8*0,5=-4
11)y(1)=1+1=2
y`=4x³+1
y`(1)=4+1=5
Y=2+5(x-1)=2+5x-5=5x-3
12)f(1)=1
f`(x)=1/(2√x)
f`(1)=1/2
Y=1+1/2(x-1)=1+1/2x-1/2=1/2x+1/2
Y(31)=1/2*31+1/2=32*1/2=16
13)f`(x)=9-x²≥0
x²=9
x=+-3
_ + _
------------------------------------------------------
-3 3
x∈[-3;3]
14)(√x-4/√x)`=1/2√x +2/√x³=(x+4)/2√x³
<em>вот решение номера один под буквой а</em>
-16.94/2.8=-6.05
................................
<span>Часть С</span><span>9) </span><span>1) [(b0,5 + 3)2 - (b0,5 - 3)2 ] / [b*[(b0,5 + 3) * (b0,5 - 3) ] = [b + 6b0,5 + 3
- b + 6b0,5 – 3] / b*(b – 9) = </span><span><span>= 12b0,5
/ b*(b – 9) = 12/</span>√b(b – 9) </span><span>2) [12/b0,5(b – 9)] * (b – 9)/b0,5
= 12 / b</span>
<span><span>10) </span>√<span>(9x2 – 6x + 1) = x2 + 1</span></span><span>(√<span>(9x2 – 6x + 1) )2
= (x2 + 1)2</span></span><span>9x2
– 6x + 1 = x4 + 2x2 + 1</span><span>x4
- 7x2 + 6x = 0</span><span>x(x3
– 7x + 6) = 0</span><span>x1
= 0</span><span>x3
– 7x + 6 = 0</span><span>x2
= 1</span><span> x3 – 7x +
6 <u>Ix
- 1
-(x3 – x2</u>) x2
+ x - 6
x2 – 7x
<u>-(x2 – x)</u>
- 6x + 6
<u>-(-6x + 6)
</u> 0</span><span>x3
– 7x + 6 = ( x – 1)( x2 + x – 6)</span><span> x2 + x – 6 = 0</span><span>x4 = 2</span><span>Ответ: x1 = 0; x2 = 1; x3 =
- 3; x4 = 2</span>
<span> </span>
3х(х+4)=0
3х=0 или х+4=0
х=0 х=-4