√4x-x²≥0
x-1≠0
x(4-x)≥0
x≠1
x∈[0,4]
D(y)= [0,1)∪(1;4]
Ответ:
(a-1)^2-(a+1)(a-2)
a^2-2a+1-(a^2-2a+a-2)
a^2-2a+1-(a2-a-2)
a^2-2a+1-a^2+a+2
-a+3
10-(9х+2)=47
10-9х-2=47
8-9х=47
-9х=47-8
-9х=39
х=-13/3
(3х+2)-(8х+6)=14
3х+2-8х-6=14
-5х-4=14
-5х=14+4
-5х=18
х=18:(-5)
х=-3,6