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<em>Решение приложено</em>
<em>===========================================================</em>
Sn=(b1*(1-q^n))/1-q
b1=36
b2=-18,9
q=b2/b1=-18,9/36
q=-0,525
n=8
S8=(36*(1-(-0,525)^8)/1-(-0,525)
S8=(36*0,994)/1,525=23,4703
<span>14(2y-3)-5(y+4)=2(3y+5)+5y
28y-42-5y-20 = 6y+10+5y
28y-5y-5y-6y=42+20+10
12y=72
y= 72\12
y=6
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