Відповідь:
12,625г
Пояснення:
Дано: | xг 2г
m(O₂)=2 г | 2KNO₃--->2KNO₂+O₂↑
---------------| 2*101 32
m(KNO3)-?|
| Отсюда: х= 2*2*101/32=12,625 г
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Держи уравнение взаимодействия аминокислот
Решение:
<span>w
(H) = 100\% - w (C) = 100\% - 85,7= 14,3\%</span>
<span>Mr
(в-ва) = 28 ∙ 2 = 56</span>
<span>n
(C) = 85,7\% ∙ 56 \12 ∙ 100\% = 4</span>
<span>n
(H) = 14,3\% ∙ 56\1 ∙ 100\% = 8</span>
<span>n
(C) : n (H) = 4:8 = CxHy = С4H8</span>
<span>ответ: 2 )) С4H8– бутен</span>