3 1/2 - 1 2/3 = 3 3/6 - 1 4/6 = 2 9/6 - 1 4/6 = 1 5/6
D=a2-a1=4-10=-6
S16=(2a1+15d)*16/2=(20-90)*8=-70*8=-560
<em>у=0</em>
<em>0=-(4/7)х-12</em>
<em>(4/7)х=-12</em>
<em>х=-(7*12)/4</em>
<em>у=-21</em>
<em>Ответ точка (-21;0)</em>
∫(dx/(x²+x-6))=∫dx/(x²+2*x*(1/2)+1/4-1/4-6)=∫(dx/((x+1/2)²-25/4)=
=∫(dx/(-(5/2)²-(x+1/2)²).
Используем формулу "Высокого логарифма":
∫(dx/(a²-x²)=(1/(2a))*(ln|a+x|/ln|a-x|)+C x≠a
(1/(2*5/2))*(ln|(-5/2+x+1/2)|/ln|(-5/2-x-1/2|)=
=(ln|x-2|/ln|-x-3|)/5==(ln|x-2|/ln|-(x+3)|)/5=(ln|x-2|/ln|x+3|)/5.