(cⁿ)⁴*c^5:(c²)ⁿ=c⁴ⁿ*c^5:c²ⁿ=c^7
F(x) = x^5+1 / 5+1 - 2x^2 / 2 +c
.................................
A+b=7
a=7-b
1/2*ab=6
ab=12
(7-b)b=12
D=49-48=1
a+3=7. a=4
a+4=7. a=3
Ответ. катеты равны 4 и 3
{6x-3≥3
{-5x≤-10
6x-3≥3
6x≥3+3
6x≥6
x≥6 : 6
х≥1
-5х≤-10
х≥ -10 : (-5)
х≥2
\\\\\\\\\\\\\\\\\\\\\\\\\\
--------- 1 --------- 2 ----------
\\\\\\\\\\\\\\\
x≥2 или х∈[2; +∞)