Ответ будет: - 0,8. решение во вложении
1)безымянный вот этот ответ если считать правильней то можно сказать это либо левый либо безымянный
Решение. Способ 1<span><span>f′</span>(x)=<span><span>(<span><span>4⋅x−7 / </span><span>x2</span></span>)</span>′</span>=
</span><span>=(<span><span><span><span>(4⋅x−7)</span>′</span>⋅<span>x2</span>−<span>(4⋅x−7)</span>⋅<span><span>(<span>x2</span>))</span>′ / </span></span><span><span>(<span>x2</span>)</span>2</span></span>=
</span><span>=<span><span><span><span>(4⋅x)</span>′</span>⋅<span>x2</span>−<span>(4⋅x−7)</span>⋅2⋅x</span><span><span>(<span>x2</span>)</span>2</span></span>=
</span><span>=<span><span>4⋅<span>x2</span>−<span>(4⋅x−7)</span>⋅2⋅x / </span><span><span>(<span>x2</span>)</span>2
</span></span></span>Ответ:<span>f′</span>(x)=<span><span>4⋅<span>x2</span>−<span>(4⋅x−7)</span>⋅2⋅x / </span><span><span>(<span>x2</span>)</span><span>2</span></span></span>
1) x²-5x=0
x(x-5)=0
x=0 x=5
2)2x²-8x=0
2x(x-4)=0
x=0 x=4
3)4x²-20x=0
4x(x-5)=0
x=0 x=5
4)7x²-42x=0
7x(x-6)=0
x=0 x=6
5)3x²+18x=0
3x(x+6)=0
x=0 x=-6
6)6x²+24x=0
6x(x+4)=0
x=0 x=-4
7)7x²-14x=0
7x(x-2)=0
x=0 x=2
8)3x²+12x=0
3x(x+4)=0
x=0 x=-4
<span>1) (0,1-х)(х+0,1)=-(x-0.1)(x+0.1)=-(x²-0.01)=0.01-x²
2)</span><span> (1,2-а)(1,2+а)</span>=1.44-a²
3) <span> (1/3-m)(1/2m-3)</span>=-1/2m²+1/6m+3m-1=-1/2m²+19/6m-1=-1/6(3m²-19m+6)