<span>1/2log_0.4(5*x+1)=log_0.4(x-1)
</span>√(5x + 1) = x - 1
ОДЗ: x - 1 > 0, x > 1
(√(5x + 1))^2 = (x - 1^2
5x + 1 = x^2 - 2x + 1
x^2 - 7x = 0
x(x - 7) = 0
x1 = 0
x2 = 7
4(2-у)=10
8-4у=10
4у=8-10
4у=-2
у=-0.5
3х2y-3yz2 = 3y(x2-z2)= 3y(x-z)(x+z)
(a²+4)/(a²-4)-a/(a+2)=(a²+4)/((a+2)(a-2)-a/(a+2)=(a²+4-a*(a-2))/((a+2)(a-2))=
=(a²+4-a²+2a)/((a+2)(a-2))= (2a+4)/((a+2)(a-2))=2*(a+2)/((a+2)(a-2))=2/(a-2).
<span>х^4+6х^3=0
x^3(x+6)=0
x=0 или х+6=0 х=-6
</span>