Х+5у=7⇒х=7-5у
3х+2у=-5
а)3*(7-5у)+2у=-5
21-15у+2у=-5
13у=26
у=2
б)х=7-5*2
х=-3
1/(1+√2) = (√2–1)/((√2–1)(√2+1)) = (√2–1)/(2–1) = √2–1,
1/(√2+√3) = (√3–√2)/((√3–√2)(√3+√2)) = (√3;–√2)/(3–2) = √3–√2,
. .
1/(√2004+√2005) = (√2005–√2004)/((√2005–√2004)(√2005+√2004)) = (√2005–√2004)/(2005–2004) = √2005–√2004.
<span>Сумма равна √2–1+√3–√2+…+√2005–√2004 = √2005–1.</span>
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