Task/24848956
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y =5 +√29sin2x - √7cos2x =5 +6((√29)/6 *sin2x - (<span>√7)/6 *cos2x) =
</span>5 +6(sin2x *cosα -sinα *cos2x) = 5 +6sin(2x - <span>α</span><span> ) , где</span>α =arctq√(7/29)<span>
-1 </span>≤ y ≤ 11 ⇒ 13 целых чисел
а84=а1+d(84 - 1) = -0,32+ (-0,02)84=2
4х - 5у = 1 4х-5у =1
2х-3у=2 | * -2 -4х +6у = -4
- 5 у+ 6у = -3 4х - (-3) *5 = 1
у = -3 4х + 15 = 1
4х = -16
х = -4
Ответ(-4;-3)