1)(3-x)(x+3)+(x-2)²=1
3x+9-x²-3x+x²-4x+4=1
-4x+13=1
-4x=-12
x=3
2)x²+3x=0
x(x+3)=0
x+3=0
x=-3
3)x³-5x²-x+5=0
x³-5x²=x-5
x²(x-5)=x-5
x²=1
x=1
<span>1) (1/9+b)^2 =1/81+2/9b+b</span>²<span>
,2) (k/2-t/5)^2=k</span>²/4-kt/5+t²/25<span>
3) (y+3 1/4)^2=y</span>²+6.5y+169/16<span>
4) (4 1/2+t)^2=81/4+9t+t</span>²
36z²+2=(3z+1)(12z+3)
36z²+2=36z²+9z+12z+3
36z²- 36z² -9z-12z=3 -2
-21z=1
z= - 1/21
Ответ: - 1/21