Ответ:
Объяснение:
1.
a) 39x³y/26x²y²=1,5x/y
b)
5y/(y²-2y)= 5y/((y(y-2))= 5/(y-2)
c)
(3a-3b)/(a²-b²)= 3(a-b)/(a-b)(a+b)=3/(a+b)
2.
a)
(3-2a)/2a - (1-a²/a ) = [a(3-2a)-2(1-a²)]/2a² = (3a-6a²-2+2a²)/2a²=
=(-4a²+3a-2)/2a²
b)
1/(3x+y) - 1/(3x-y) =[3x-y-(3x+y)/(9x²-y²)= (3x-y-3x-y)/(9x²-y²)=
=-2y/(9x²-y²)
c)
(4-3b)/(b²-2b) +3/(b-2)= (4-3b)/b(b-2) + 3/(b-2)=(4-3b+3b)/b(b-2)=
=4/(b²-2b)
А(3;-3;5)
5а(5×3;5×(-3);5×5)=(15;-15;25)
в(3;0;5)
6в(18;0;30)
М=(18-15;0-(-15);30-25)=(3;15;5)
сравни с другими
2x-1
log1/2_________>log(1/2)1/2
x+1
1/2<1⇒ 2x-1
_______<1/2
x+1
2x-1-0,5x-0,5
___________,<0
x+1
1,5x-1,5
_______<0
X+1
1,5(x-1)(x+1)<0
(x-1)(x+1)<0
x1=1 x2=-1
x∈(-1 ;1) ОДЗ Х≠-1 х∈(-∞ -1)∨(0,5;∞)
ответ х∈(0,5; 1)