Х²+3+11х>0
х²+11х+3=0
D=11²-4•3=121-12=109
x= -11-√109/2
x= -11+√109/2
5√2+2√16×√2-√49×√2=5√2+2×4√2-7√2=8√2-2√2=6√2
3x² + 13x - 10 =0
Ищем дискриминант
D = 13² - 4*3*(-10) = 169 + 120 = 289
x1 = (-13 + 17)/6 = 4/6 = 2/3
x2 = (-13-17)/6 = -30/6 = -5
Ответ:........................