36а^2+120ах+100х^2.......
Область определения:
а) y = √(x + 4)
x + 4 ≥ 0
x ≥ - 4
D(y) = [-4 ; + ≈)
в) y = (2x + 1)^(1/3)
D(y) = ( - ≈; + ≈) или D(y) = R
д) y = 4/(2x - 5)^(1/4)
2x - 5 > 0
2x > 5
x > 2,5
D(y) = (2,5 ; + ≈)
-6х^2-1,4х+7,4=0
6x^2 + 1.4x - 7.4 = 0
D = 1.4^2 + 4*6*7.4 = 1.96 + 177.6 = 179.56 = 13.4^2
x1,2 = (-1.4 +/- 13.4) / 12
x1 = 1
x2 = -14.8/12 = -7.4 / 6
Ответ:
Б) 1
<span />
15-5√3+3√3-3-3-1+2<span>√3=8</span>
<span>а)3х(2х-1)-6х(7+х)=90
6х^2-3х-42х-6</span>^2=90
45х=90
х=2
б)<span>1,5х(3+2х)=3х(х+1)-30
4,5х+3</span>х^2=3х^2+3х-30
4,5х+3х^2-3х^2-3х=-30
1,5х=-30
х=-20
в) <span>5х(12х-7)-4х(15х-11)=30+29х
60</span>х^2-35х-60х^2+44х-29х=30
-20х=30
х=-1.5
<span>г)24х-6х(13х-9)=-13-13х(6х-1)
</span> 24х-78х^2+54х+78х^2-13х=-13
65х=13
х=-0,2