=3x2+5x-1=x2-4x
3x2+5x-1-x2+4x=o
2x2+9x-1=o
Lim(x->0)(sin(4x)*sin(2x))/(x^2+x^3)=l0/0I=Isin(2x)~2x,sin(4x)~4xI=lim(x->0)(2x*4x)/(x^2*(1+x))=lim(x->0)8/(1+x)=8/(1+0)=8
Х=4+y
(4+y)^2+y^2=10
16+8y+y^2+y^2-10=0
2y^2+8y+6=0
D=64-4*2*6=64-48=16
x1=(-8+4)/4=-1
x2=(-8-4)/4=-3
y+4=-1 y+4=-3
y=-7
y1=-5
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ответ:(-1;-5) (-3;-7) </span>