[(5x)^7 * (5x)^4 * 25] / [(25x^2)^4 * 125x^2 = 100
[ 5^7 * x^7 * 5^4 * x^4 * 5^2] / [(5^2)^4 * (x^2)^4 * 5^3 * x^2] = 100
[ 5^(7+4+2) * x^(7+4)] / [5^(8+3) * x^(8+2)] = 100
[5^(13) * x^(11)] / [5^(11) * x^(10)] = 100
5^(13-11) * x^(11-10) = 100
5^2 * x = 100
<span>x = 100/25 = 4</span>
<span>7x</span>²<span> + 6x + 1 = 0</span>
D = 6²<span> - 4·7·1 = 8</span>
<span><span><span>x1 = (</span><span>-6 - √8)/2*7</span> = <span><span>-3/</span>7</span> - <span>17</span><span>√2</span> ≈ -0.63060
</span></span><span><span>x2 = (</span><span>-6 + √8)/2*7</span> = <span><span>-3/</span>7</span> + <span>17</span><span>√2</span> </span>≈ -0.22654<span>
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Первое 4
<span>второе 3
</span><span>третье 3
</span><span>четвёртый 3
</span>
У=ln х-1/х+1y'=1/x+1/(x+1)^2=(x^2+3x+1)/x(x+1)y'=1/x+1/x^2=x^2+x=(1+x)/x^2<span>y'=(2*sqrt(x^2+1)-2x(2x)*(1/2)/sqrt(x^2+1))/(x^2+1)=sqrt(x^2+1)/(x^2+1)^2</span>
25y^2-(25y^2-20y+4)=0
25y^2-25y^2+20y-4=0
20y=4
y=4/20=1/5=0,2
Ответ: y=0,2