Sinx/(1+cosx)+cosx/sinx=(sin²x+cosx+cos²x)/[sinx(1+cosx)]=
=(1+cosx)/[sinx(1+cosx)]=1/sinx=1:(-0,6)=-5/3
sinx=-√(1-cos²x)=-√1-0,64)=-0,6
1) 7/(x^3/3)=> 21/x^3
2) 12* корень из x
а)9*х^2*у/10 (тут все возводится)
б)<span>-2<span>√</span>а+<span>√</span>b +3<span>√</span>b =4<span>√</span>b - 2<span>√</span>а</span>
<span>в)3<span>√</span>2+<span>√</span>(16*2) - <span>√</span>(25*2)=3<span>√</span>2 + 4<span>√</span>2 - 5<span>√</span>2 = 2<span>√</span>2</span>
<span>г)<span>х+2<span>√</span>х*у +у-2<span>√</span>ху=х+у</span></span>
(Х-3)(Х+2)= Х-3•х+2= х•х= 3+2= 2х=6
Х=6:2=3
Х=3
Ответ : Х=3