<span>S -> SO2 -> SO3 -> H2SO4 -> JnSO4</span>
1) 4Al + 4O2 = 2Al2O3
2) Al2O3 + 3H2SO4 = Al2(SO4)3 + 3H2O
3) Al2(SO4)3 + 6KOH = 3Al(OH)3 + 3K2SO4
4) 2Al(OH)3 = Al2O3 + 3H2O
5) Al2O3 + 6HNO3 = 2Al(NO3)3 + 3H2O
<span>Дано:</span>
w(Cr) = 35,37\%
w(P) = 21,1\%
O
<span>Найти: CrxPyOz</span>
Решение:
<span>w(O) = 100\% - (w(P) + w(Cr)) = 100\% - (35,37\%
+ 21,1\%) = 43,53\%</span><span>
</span><span>n(Cr) = 35,37\%\52
= 0,68</span>
<span>n(P) = 21,1\%\31 =
0,68</span>
<span>n(O) = 43,53\16 = 2,72</span>
<span><span>CxHy = n(Cr) : n(P) : n(O) = 0,68 : 0,68 : 2,72 = 1: 1: 4 = </span>→ Cr1P1O4</span>
<span>Ответ: CrPO4 - ортофосфат хрома (III)</span>