Br2--HBr--Zn--ZnO--Zn(OH)2--K2ZnO2
1)Br2+H2=2HBr
2)2HBr+Zn=ZnBr2+H2
ZnBr2=(эл.ток)=> Zn+Br2
3)2Zn+O2=2ZnO
4)ZnO+2HCl=ZnCl2+H2O
ZnCl2+2RbOH=Zn(OH)2+2RbCl
5)Zn(OH)2+2KOH=K2ZnO2+2H2O
2HNO₃ + Cu(OH)₂ = Cu(NO₃)₂ + 2H₂O1)Cu²⁺ + 2OH⁻ + 2H⁺ + 2NO₃⁻ = Cu²⁺ +2NO₃⁻ + 2H₂0
2)OH⁻ + H⁺ = H₂<span>0
</span>
<span>AgNO</span>₃ + NaCl = NaNO₃ + AgCl↓ 1)Ag⁺ + NO₃⁻ + Na⁺ + Cl⁻ = Na⁺ + NO₃⁻ + AgCl↓ <span>2)Ag</span><span>⁺</span><span> </span><span>+</span><span> </span><span>Cl</span><span>⁻</span><span> </span><span>=</span><span> </span><span>Ag</span><span>Cl</span><span>↓</span><span>
</span>
Na₂SO₃ +
2H₂SO₄ = 2NaHSO₄ + SO₂↑ + H₂O
1)2Na⁺ +
SO₃²⁻ + 4H⁺ + 2SO₄²⁻ = 2Na⁺ + 2HSO₄⁻ + SO2↑ + H2O
<span>2)SO</span><span>₃</span><span>²</span><span>⁻</span><span> + 4H</span><span>⁺</span><span> + 2SO</span><span>₄</span><span>²</span><span>⁻</span><span> = 2HSO</span><span>₄</span><span>⁻</span><span> + SO</span>₂<span>↑ + H</span>₂<span>O</span>
Дано:
m(пищевой соды)- 42г
Найти
n-?
Решение:
n=m/M (поделить в дроби)
M(NaOH)=23+16+1=40
n(NaOH)=42/40=1,05 моль
Вроде так но не уверена