1) а3 -0,027b3
2)64x3 +1
3) = (1-XY)(1 +XY +X2Y2) / Z(XY-1) =(1+XY+X2Y2)/-Z
x³-y³=26
x²+xy+y²=13
x³-y³ = (x-y)(x²+xy+y²)=(x-y)*13 = 26
x-y = 26/13 = 2
x = y+2
(y+2)²+(y+2)y+y²=13
y²+4y+4+y²+2y+y² = 13
3y²+6y-9 = 0
y²+2y-3 = 0
(y-1)(y+3) = 0
y₁ = 1, x₁= 3
y₂ = -3, x₂=-1
Решение во вложенииииииииииииииииииииииииии
при t=0 уравнение имеет один корень х=0