(5y+4)(1,1y-3,3)=0
5y+4=0 или 1,1y-3,3=0
5y=-4 1.1y=3.3
y=-4/5 y=3.3:1,1
y=-0,8 y=3
Ответ: -0,8;3
<span>-9а² + 4b²</span>= 4b²-9а² =(2b+3a)(2b-3a)
-0.09х²у² + 1=1<span>-0.09х²у² =(1-0.3xy)</span>(1+0.3xy)
5x - 6x^2 = 0
x (5 - 6x) = 0
x1 = 0 ;
5 - 6x = 0
- 6x = - 5
x2 = 5/6
Ответ
0; 5/6