Решение
1) sinx = - 1/2
x = (-1)^n *arcsin(-1/2) + πn, n ∈ Z
x = (-1)^(n+1) *arcsin(1/2) + πn, n ∈ Z
x = (-1)^(n+1) *(π/6)<span> + πn, n ∈ Z
</span>2) 3tgx = 0
tgx = 0
x = πk, k ∈ Z
3) cos4x = 0
4x = π/2 + πn, n ∈ Z
x = π/8 + (πn)/4, n ∈ Z
4) cos(3x - π/6) = - 1
3x - π/6 = π + 2πk, k ∈ Z
<span>3x = π/6 + π + 2πk, k ∈ Z
</span>3x = 7π/6 + <span>2πk, k ∈ Z
x = 7</span>π/18 + (2πk)/3, k ∈ Z
<span>12х-х=55
11х=55
х=5
</span><span>2(х+3)=16
</span>2х+6=16
2х=10
х=5
<span>5(х+3)+7=3(х+12)
</span>5х+15+7-3х-36=0
2х-14=0
х=7
См. в приложении.
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10 * 5 - 15 = 35
44 + 6 + 17 = 67
15 : 3 + 8 = 13
74 - (8 + 52) = 14
13 + 4 + 27 = 44
67 - 29 - 24 = 14
14 : 7 * 5 = 10
35 - (8 + 12) = 15
Берешь n=1 подставляешь:
1-1-1+1=-2
Следовательно утверждение неверно