Решение 1) sinx = - 1/2 x = (-1)^n *arcsin(-1/2) + πn, n ∈ Z x = (-1)^(n+1) *arcsin(1/2) + πn, n ∈ Z x = (-1)^(n+1) *(π/6)<span> + πn, n ∈ Z </span>2) 3tgx = 0 tgx = 0 x = πk, k ∈ Z 3) cos4x = 0 4x = π/2 + πn, n ∈ Z x = π/8 + (πn)/4, n ∈ Z 4) cos(3x - π/6) = - 1 3x - π/6 = π + 2πk, k ∈ Z <span>3x = π/6 + π + 2πk, k ∈ Z </span>3x = 7π/6 + <span>2πk, k ∈ Z x = 7</span>π/18 + (2πk)/3, k ∈ Z