m-1/1-m = M-1 / -(M -1) = -1
2a(3a-5b)-3a(2a-b)-12b(1/4-a)-6a(2b-1/3)=12/5=2 2/5= 2,4
<span>sin3x*cos2x=sin5x
</span><span>sin3x*cos2x=sin(3x+2x)
</span>sin3x*cos2x=sin3x cos2x+sin2x cos3x
sin2x cos3x=0
1) sin2x=0 2x=πn, n∈Z x=(π/2)n, n∈Z
2) cos3x=0 3x=π/2+πn, x=π/6+πn/3 , n∈Z
√3 - √6 * cos x = 0
√6 * cos x = √3
cos x = √3 / √6
cos x = √(3/6)
cos x = √(1/2)
cos x = 1 / √2
x = ± arccos 1/√2 + 2pi n, n e Z
x= ± pi/4 + 2pi n, n e Z