9y²-12xy-45x²=(3y)²-2*3y*2x+4x²-4x²-45x²=(3y-2x)²-49x²=(3y-2y)²-(7x)²=
=(3y-2x-7x)(3y-2x+7x)=(3y-9x)(3y+5x).
Y=
D(x):3x^2+x≠0
x(3x+1)≠0
x≠0 x≠-1/3
x∈(-∞;-1/3)∪(-1/3;0)∪(0;+∞)
Метод Лягерра, точность <span> 1e-3</span>
<span>x1 ≈ 0.666666552553487
<span>P(x1) ≈ 0 <span>iter = </span>4
</span><span>x2<span> ≈ 0.749999727053003 − i ∙ 0.66143770861557
</span>P(x2) ≈ 0 <span>iter = </span>3
</span><span>x3<span> ≈ 0.750000123124048 + i ∙ 0.661438012106969
</span>P(x3) ≈ 0 <span>iter = </span>3
</span><span>x4<span> ≈ 1.0000003286761
</span>P(x4) ≈ 0 <span>iter = </span>1
</span><span>x5<span> ≈ 1.49999993526003
</span>P(x5) ≈ 0 <span>iter = </span>1</span></span>
Точки называются не кризисными, а критическими.