25+40х+16х^2=36х+45-84х^2-105х
Решение на 1 номер
х^-25-х^-3х<6
-25-3х<6
-3х<6+25
-3х<31
х>-31/3
(b-6)(b*b +6b+36)-(b-2)(b+3) = b^3 + 6b^2 +36b - 6b^2 - 36b - 216 - (b^2 + b - 6) = b^3 + 6b^2 +36b - 6b^2 - 36b - 216 - b^2 - b + 6 = b^3 - b^2 - b - 210
Lim(x->0)(sin(4x)*sin(2x))/(x^2+x^3)=l0/0I=Isin(2x)~2x,sin(4x)~4xI=lim(x->0)(2x*4x)/(x^2*(1+x))=lim(x->0)8/(1+x)=8/(1+0)=8